How to Calculate the quantity of cement , sand and brick in one meter cubic volume ?

Calculate the quantity of cement , sand and brick in one meter cubic volume

Given

- Mortar ration = 6:1 = 7

- mortar thickness = 10mm=0.01m

- density of cement = 1440

Solution

brick of 1 m³

- volume of brick = length X width x

thickness ( without mortar)

- volume of brick = L x W x T

- volume of brick = 0.19 x 0.09 x 0.09

- volume of brick = 0.001539 m³

With mortar

Volume of brick add 0.01m in the three dimensions

(0.19+0.01) x (0.09+0.01) x (0.09+0.01)

= 0.2m x 0.10m x 0.10m

Now let’s compute the volume

- volume of brick = L x W x T

- volume of brick = 0.2m x 0.1m x 0.1m

- volume of brick = 0.002 m³

- Number of brick 1m³ = 1/ 0.002 =

#500 of brick 🧱

➪ Volume of mortar

= 1 - ( 500x0.001539) .... Dry VOLUME

Thus; 1 is total meter cube of volume

- 500 is total number of brick 🧱

- dry volume of brick without mortar

= 1- (500x 0.001539) = 0.2305m³

☞ For Wet volume of mortar we Take

40% ( 10% shrinkage & 30%

wastage )

40% = 40/10 = 0.4 ; so we multiply to dry volume with 1 + 0.4 = 1.4

Wet volume

= 0.2305m³ x 1.4 = 0.3227m³

Cement of 1m³

➪ I have given you the ratio yesterday

We assumed 6:1 so it add up 7

=6+1 = 7

-Quantity of cement = 1/7 x 0.3227m³

- Quantity of cement = 0.0461m³

- 0.0461m³ x 1440kg/m³ = 66.384kg

* Weight of cement = 66.384kg

- Number of bags = 66.38kg/ 50kg

- Number of bags = 1.32 app 2 bags

Sands for 1m³

- Quantity of sand = 6/7 x 0.3227m³

- quantity of sand = 0.2766m³

• if we want to quantify it with kilogram

- the density of sand is 1442kg/m³

Mass = density x volume

Mass= 1442kg/m³ x 0.2766m³

Mass = 398.8kg app 400kg

For 1m³ volume

➪ total number of brick = 500

➪ quantity of cement = 66.38 kg (mass)

➪ quantity of sand = 400 kg (mass)

➪ quantity of cement = 0.0461m³ (volume)

➪ quantity of sand = 0.2766m³ (volume)

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